Question :-- Solve the problem: 4(10 + 15 ÷ 5× 4 – 2×2)=?
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72
-
48
-
64
-
144
Solution:--
4× 18 = 72 Ans
Question :--
Monthly premium of a PLI policy comes to Rs 4,180/- including GST of 4.5%. what will be net premium excluding GST?
PLI पॉलिसी का मासिक प्रीमियम 4.5% GST सहित 4,180/- रुपये आता है। GST के बिना प्रीमियम क्या होगा?
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Rs. 3090
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Rs. 4000
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Rs. 3080
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Rs. 4010
Solution:--
Original Premium == = 4000 Ans
Question :--
A carpenter took loan at 10% per annum at simple interest. After 5 years he settled the loan by paying Rs 5250/-. What was the principal amount?
एक बढ़ई ने 10% वार्षिक साधारण ब्याज पर ऋण लिया। 5 साल बाद उसने 5250/- रुपये का भुगतान करके ऋण का निपटान किया। मूल राशि क्या थी?
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Rs. 3250
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Rs. 3500
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Rs. 3750
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Rs. 3100
Solution:--
Given Amount = 5250 Rs., Principal (P) = ?R = 10%, T= 5 YearsNow SI = Amount - Principal = 5250 – PAgain SO = ⇒5250 - P = P = 2 (5250 - P)P = 10500 – 2 P ⇒ 3P = 10500And P = 10500/3 = 3500 Ans
Question :--
Two bats and three balls cost Rs 860/-. Four bats and a ball cost Rs 1120/-, Find the cost of a bat and a ball separately.
दो बल्ले और तीन गेंद की कीमत 860/- रुपये है। चार बल्ले और एक गेंद की कीमत 1120/- रुपये है, एक बल्ले और एक गेंद की कीमत अलग-अलग ज्ञात करें।
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Bat Rs 150 and Ball Rs 100
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Bat Rs 250 and Ball Rs 120
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Bat Rs 120 and Ball Rs 250
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Bat Rs 250 and Ball Rs 80
Solution:--
Let Cost Of One Bat = x (Bat)And Cost Of One Ball Y (Ball)A-T-Q. 2x + 3y =860 ---- (1)4x + Y =1120 -----(2)Multiplying Equation① With (2) We Get2 (2x + 3y) = 2 × 8604x + 6y = 1720 ---- (3)Now, subtract (2) From ③ We Get4x + 6y = 1720- 4x + Y = 11205Y = 600Y = 600/5 = 120 Rs. Put in (1) we get2x + 3 (120) = 860 ⇒ 2x+360 = 860⇒ 2x+860 = 360⇒ 2x = 500 ⇒x=250 Ans
Question :--
By selling 90 ball pens for Rs 160 a person loses 20%. How many ball pens should be sold for Rs 96 so as to have a profit of 20%
160 रुपये में 90 बॉल पेन बेचने पर एक व्यक्ति को 20% की हानि होती है। 96 रुपये में कितने बॉल पेन बेचे जाएं ताकि 20% का लाभ हो
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34
-
38
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36
-
32
Solution:--
SP of 90 ball pens = 160 rsSP of 1 ball pens = 160/90 = 16/9 RsLess = 20%CP Of one pen ==2nd conditionGain = 20%SP of one pen =s.Now, SP of 1 pen = 8/3 Rs1 Rs = 3/8 PensRs Ans
Question :--
Distance between two stations X and Y is 300 km. A train leaves the station X with a speed of 40 KM/hr. At the same time another train departs from station Y with the speed of 50 KM/hr. How much time will these two trains take to cross each other?
दो स्टेशनों X और Y के बीच की दूरी 300 किमी है। एक ट्रेन स्टेशन X से 40 किमी/घंटा की गति से निकलती है। उसी समय दूसरी ट्रेन स्टेशन Y से 50 किमी/घंटा की गति से प्रस्थान करती है। इन दोनों ट्रेनों को एक दूसरे को पार करने में कितना समय लगेगा?
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3 hour 40 mins
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3 hour 20 mins
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2 hour 20 mins
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3 hour 45 mins
Solution:--
Speed of 1st train = 40 km/h→time taken by 1st train = 300/40 ⇒ 7.5 ⇒ 7 hours 30 mins.speed of 2nd train = 50 km/h.→time taken by 2nd train = 300/5 = 6 hoursHalf of time of train 1 = 3h 15 minsHalf of time of train 2 = 3 hoursSo, approximately they meet at 3h 20 minutes
Question :--
A bus moving at 48 km/hr completes a journey in 10 Hours. By how much speed of this bus should be increased to complete this journey in 8 hours? --- 48 किमी/घंटा की गति से चलने वाली एक बस 10 घंटे में यात्रा पूरी करती है। इस यात्रा को 8 घंटे में पूरा करने के लिए इस बस की गति कितनी बढ़ानी होगी?
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8 KM/hr
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12 KM/hr
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10 KM/hr
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15 KM/hr
Solution:--
speed = 48 km/h, Time = 10 hoursTotal distance covered = speed × time = 48 × 10 = 480 km2nd conditionDistance = 480 k.m., Time = 8 hours.Speed = D/t = 480/8 = 60 km/hSo, increasement in speed = 60-48 = 12km/h Ans
Question :--
A man's wage was reduced by 50%. Again the reduced wage was increased by 50%. Find his fixed loss in terms of percentage.
एक आदमी का वेतन 50% कम हो गया। पुनः घटी हुई मज़दूरी में 50% की वृद्धि की गई। प्रतिशत के रूप में उसकी निश्चित हानि ज्ञात कीजिए?
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75%
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50%
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0%
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25%
Solution:--
Let his wage = 100Rs.After 50% Reduce, the new wage = = 50 RsAfter 50%. Increase, new wage=50 +50×50100 = 50 + 25 = 75 RsNet loss = 100-75 = 25 Rs
Question :--
Solve the problem: (15 × 32 ÷ 2 ×5) ÷ 75 = ?
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18
-
14
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16
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12
Solution:--
A = 15 daysB = 10 daysTotal Work = lcm of A & B = 30 UnitA’s one day work = 30/15 = 2 UnitB’s one day work = 30/10 = 3 Unit(A+B)’s one day work = 2+3 = 5 UnitSo, time taken by(a + b) to complete 30 units work = 30/5 = 6 day
Question :--
"A" finishes his work in 15 days while "B" takes 10 days. How many days will the same work be done if they work together?
"A" अपना काम 15 दिनों में पूरा करता है जबकि "B" को 10 दिन लगते हैं। यदि वे एक साथ कार्य करें तो समान कार्य कितने दिनों में पूरा होगा?
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5
-
6
-
8
-
7
Solution:--
= 16 Ans
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